# Q. 6.    $DL$ and $\inline BM$ are the heights on sides $\inline AB$ and $\inline AD$ respectively, of parallelogram $\inline ABCD$ (Fig 11.24). If the area of the parallelogram is             $\inline 1470\; cm^{2}.$ $\inline AB=35\; cm$ and $\inline AD=49\; cm,$ find the length of $\inline BM$ and $\inline DL.$

R Riya

We know that

Area of parallelogram  $= base \times height$

Here,

Base of parallelogram(AB) = 35 cm

and

Height of parallelogram(DL) = h cm

$\Rightarrow 1470 = 35 \times h$

$\Rightarrow h = \frac{1470}{35} = 42 \ cm$

Similarly,

Area is also given by $AD \times BM$

$\Rightarrow 1470 = 49 \times BM$

$\Rightarrow BM = \frac{1470}{49} = 30 \ cm$

Therefore, the value of BM and DL are  is  30cm and 42cm respectively

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