# Q8.    Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet?

The steps of constructions are:

(i) Draw the circle with O and radius 4 cm.

(ii) Draw any two chords $\bar{AB}$ and $\bar{CD }$in this circle.

(iii) Taking A and B as centres and radius more than half AB, draw two arcs which intersect each other at E and F.

(iv) Join EF. Thus EF is the perpendicular bisector of chord $\bar{CD }$.

(v) Similarly draw GH the perpendicular bisector of chord $\bar{CD }$.

These two perpendicular bisectors meet at O, the centre of the circle.

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