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# Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA equals OB. Draw the perpendicular bisectors of OA and OB . Let them meet at P. Is PA equals PB?

Q9.    Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of $\overline{OA}$ and $\overline{OB}$. Let them meet at P. Is PA = PB ?

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The steps of constructions are:

(i) Draw any angle with vertex O.

(ii) Take a point A on one of its arms and B on another such that

(iii) Draw perpendicular bisector of $\bar{OA}$ and $\bar{OB}$.

(iv) Let them meet at P. Join PA and PB.

With the help of divider, we obtained  that $\bar{PA} = \bar{PB}.$

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