# 9.8     Explain $[Co(NH_{3})_{6}]^{3+}$ is an inner orbital complex whereas $[Ni(NH_{3})_{6}]^{2+}$ is an outer orbital complex.

D Devendra Khairwa

Firstly consider  $[Co(NH_{3})_{6}]^{3+}$   :-

The oxidation state of cobalt is +3. So the electronic configuration of it will be d6.

Since (NH3) is a strong ligand so the pairing of electron will be there.

So, it has d2sp3 hybridisation and an inner orbital complex.

Now consider,$[Ni(NH_{3})_{6}]^{2+}$

The oxidation state of nickel is +3. So its electronic configuration will be d8.

Also (NH3) is a strong ligand so pairing of electrons will be seen.

Thus     $[Ni(NH_{3})_{6}]^{2+}$ is an outer orbital complex.

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