9.5    Explain on the basis of valence bond theory that   [Ni(CN)_{4}]^{2-}ion with square planar structure is diamagnetic and the [NiCl_{4}]^{2-}ion with tetrahedral geometry is paramagnetic.

 

 

 

Answers (1)

In both the compounds, the oxidation state of Nickel is +2. So it has d8 configuration. 

Now, on the basis of ligand pairing of electrons will occur. Since CN- is a strong ligand so pairing will occur but in case of  Cl- pairing will not be there as it is a weak ligand. So, the configuration of both the compounds looks like :- 

                                      

                                             

                                            

Thus  [Ni(CN)_{4}]^{2-} is a square planer and diamagnetic and  [NiCl_{4}]^{2-}  has tetrahedral geometry and is paramagnetic.

Related Chapters

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout NEET May 2022

An exhaustive E-learning program for the complete preparation of NEET..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions