Q

# Factorise the following using appropriate identities: (ii) 4y ^2 - y + 1

3.(ii) Factorise the following using appropriate identities:

(ii)    $4y^2 - 4y + 1$

Views

We can rewrite $4y^2 - 4y + 1$ as

$\Rightarrow 4y^2 - 4y + 1=(2y)^2-2\times2y\times 1+(1)^2$

Using identity  $\Rightarrow (a-b)^2 = (a)^2-2\times a\times b +(b)^2$

Here, $a= 2y \ \ and \ \ b = 1$

Therefore,

$4y^2 - 4y + 1=(2y-1)^2=(2y-1)(2y-1)$

Exams
Articles
Questions