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  2. Factorise the following using appropriate identities: (iii) x ^2 - y ^2 / 100
# NCERT

3.(iii) Factorise the following using appropriate identities:

   (iii)    x^2 - \frac{y^2}{100}

Answers (1)
G Gautam harsolia

We can rewrite   x^2 - \frac{y^2}{100}  as 

\Rightarrow x^2 - \frac{y^2}{100} = (x)^2-\left(\frac{y}{10} \right )^2

Using identity  \Rightarrow a^2-b^2 = (a-b)(a+b)

Here, a= x \ \ and \ \ b = \frac{y}{10}

Therefore,

x^2 - \frac{y^2}{100} = \left ( x-\frac{y}{10} \right )\left ( x+\frac{y}{10} \right )

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