# 9.7    $[Fe(H_{2}O)_{6}]^{3+}$ is strongly paramagnetic whereas $[Fe(CN)_{6}]^{3-}$ is weakly paramagnetic. Explain.

In both the compounds Fe has +3 oxidation state i.e., d5 configuration.

In the case of strong ligand (CN-), the pairing of electron will occur. So number of electrons left unpaired will be 1.

In case of weak ligand (H2O), pairing of electron will not there. Thus number of electrons unpaired will be 5.

We know that paramagnetic strength is directly proportional to the number of unpaired electrons.

Hence paramagnetism will be more in case of   $[Fe(H_{2}O)_{6}]^{3+}$

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