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FeSO_{4} solution mixed with (NH_{4})_{2}SO_{4} solution in 1:1 molar ratio gives the test of Fe^{2+} ion but CuSO_{4} solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu^{2+} ion. Explain why?

9.2  FeSO_{4} solution mixed with (NH_{4})_{2}SO_{4} solution in 1:1 molar ratio gives the test of Fe^{2+} ion but  CuSO_{4} solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu^{2+} ion. Explain why?

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The major difference between both the compounds is that the first compound is a salt and the other one is a coordination compound. In case of double salt compounds (Mohr's salt), the compound breaks into its constituent ions when dissolved in water, therefore it gives a positive test for the presence of Fe+2. But in case of coordination compounds, they maintain their identity in both solid and dissolved state. Thus the individual property of each constituent is lost. And therefore it doesn't give a positive test for Cu+2.

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