7.   Find:

    (a)\frac{1}{2} \; \; o\! f\; \; (i)\; \; 2\frac{3}{4} \; \; \;(ii)\; 4\frac{2}{9}            (b)\frac{5}{8} \; \; o\! f\; \; (i)\; \; 3\frac{5}{6} \; \; \;(ii)\; 9\frac{2}{3}

Answers (1)

(a) (i)\frac{1}{2} \; \; o\! f\; \;\; \; 2\frac{3}{4} \;

As we know that of is equivalent to multiply,

\frac{1}{2} \; \; o\! f\; \;\; \; 2\frac{3}{4} \;=\frac{1}{2}\times2\frac{3}{4}=\frac{1}{2}\times\frac{11}{4}=\frac{11}{8}=1\frac{3}{8}

(a)(ii)\frac{1}{2} \; \; o\! f\;\; 4\frac{2}{9}

As we know that of is equivalent to multiply,

\frac{1}{2} \; \; o\! f\;\; 4\frac{2}{9}=\frac{1}{2}\times4\frac{2}{9}=\frac{1}{2}\times\frac{38}{9}=\frac{38}{18}=\frac{19}{9}=2\frac{1}{9}

(b)(i)\frac{5}{8} \; \; o\! f\; \; 3\frac{5}{6} \; \;

As we know that of is equivalent to multiplication, so

\frac{5}{8} \; \; o\! f\; \; 3\frac{5}{6} \; =\frac{5}{8}\times3\frac{5}{6}=\frac{5}{8}\times\frac{23}{6}=\frac{115}{48}=2\frac{19}{48}

(b)(ii)\frac{5}{8} \; \; o\! f\; \;\; 9\frac{2}{3}

As we know that of is equivalent to multiplication, so

\frac{5}{8} \; \; o\! f\; \;\; 9\frac{2}{3}=\frac{5}{8}\times \frac{29}{3}=\frac{145}{24}=6\frac{1}{24}

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