3. Find:    $(i)\; \frac{7}{3}\div 2$              $(ii)\; \frac{4}{9}\div 5$                 $(iii)\; \frac{6}{13}\div 7$               $(iv)\; 4\frac{1}{3}\div 3$    $(v)\; 3\frac{1}{2}\div 4$           $(vi)\; 4\frac{3}{7}\div 7$

P Pankaj Sanodiya

As we know, The division of a number by a / b is equivalent to multiplication of that number with b / a which is also called the reciprocal of a / b. So,

$(i)\; \frac{7}{3}\div 2$

$\Rightarrow \; \frac{7}{3}\div 2=\frac{7}{3}\times\frac{1}{2}=\frac{7}{6}=1\frac{1}{6}$

$(ii)\; \frac{4}{9}\div 5$

$\Rightarrow \; \frac{4}{9}\div 5=\frac{4}{9}\times\frac{1}{5}=\frac{4}{45}$

$(iii)\; \frac{6}{13}\div 7$

$\Rightarrow \; \frac{6}{13}\div 7=\frac{6}{13}\times\frac{1}{7}=\frac{6}{91}$

$(iv)\; 4\frac{1}{3}\div 3$

$\Rightarrow \; 4\frac{1}{3}\div 3=\frac{13}{3}\div3=\frac{13}{3}\times\frac{1}{3}=\frac{13}{9}=1\frac{4}{9}$

$(v)\; 3\frac{1}{2}\div 4$

$\Rightarrow \; 3\frac{1}{2}\div 4=\frac{7}{2}\div4=\frac{7}{2}\times\frac{1}{4}=\frac{7}{8}$

$(vi)\; 4\frac{3}{7}\div 7$

$\Rightarrow \; 4\frac{3}{7}\div 7=\frac{31}{7}\div7=\frac{31}{7}\times\frac{1}{7}=\frac{31}{49}$

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