# 7. Find both the maximum value and the minimum value of on the interval [0, 3].

Given function is

Now, by hit and trial let first assume x = 2

Hence, x = 2 is one value
Now,

which is  not possible
Hence, x = 2 is the only critical value  of function
Now, we need to check the value at x = 2 and at the end points of given range i.e. x = 0 and x = 3

Hence, maximum value of function    occurs at x = 0 and vale is 25
and minimum value of function  occurs at x = 2 and value is -39

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