1. Find dy/dx  in the following: 

2 x + 3 y = \sin x

Answers (1)

Given function is 
2 x + 3 y = \sin x
We can rewrite it as
3y = \sin x - 2x
Now, differentiation w.r.t. x is
3\frac{dy}{dx} = \frac{d(\sin x - 2x)}{dx} = \cos x - 2
\frac{dy}{dx} = \frac{\cos x-2}{3}
Therefore, the answer is \frac{\cos x-2}{3}
 

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