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# Find p(0), p(1) and p(2) for each of the following polynomials: (i) p(y) = y ^2 - y + 1

2.(i)  Find p(0), p(1) and p(2) for each of the following polynomials:

(i)    $p(y)= y^2 - y + 1$

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Given polynomial is

$p(y)= y^2 - y + 1$

Now,

$p(0)= (0)^2 - 0 + 1= 1$

$p(1)= (1)^2 - 1 + 1 = 1$

$p(2)= (2)^2 - 2 + 1 = 3$

Therefore, valures of p(0), p(1) and p(2) are 1 , 1 and 3 respectively

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