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Find the amount of water displaced by a solid spherical ball of diameter (i) 28 cm

Q : 2    Find the amount of water displaced by a solid spherical ball of diameter

            (i) 28 cm 

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The solid spherical ball will displace water equal to its volume. 

Given,

The radius of the sphere = r = \frac{28}{2}\ cm = 14\ cm

We know, Volume of a sphere = \frac{4}{3}\pi r^3

\therefore The required volume of the sphere = \frac{4}{3}\times\frac{22}{7}\times (14)^3

\\ = \frac{4}{3}\times22\times 2\times 14\times 14

\\ = \frac{34469}{3} \\ = 11489\frac{2}{3}\ cm^3

Therefore, the amount of water displaced will be 11489\frac{2}{3}\ cm^3

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