Q. 11.     Find the area of the quadrilateral ABCD. Here,AC=22\; cm, BM=3\; cm,DN=3\; cm, and BM\perp AC,DN\perp AC

               

Answers (1)

Area  of  quadrilateral ABCD = Area of triangle ABC + Area of tringle ADC
 
Area of triangle ABC with base 22 cm and height 3 cm is

\Rightarrow \frac{1}{2} \times \ base \times height =\frac{1}{2} \times 22 \times 3 = 33 \ cm^2

Area of triangle ADX with base 22 cm and height 3 cm is

\Rightarrow \frac{1}{2} \times \ base \times height =\frac{1}{2} \times 22 \times 3 = 33 \ cm^2

Therefore, the area of quadrilateral ABCD is = 33+33=66 \ cm^2

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