Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the area of the region bounded by y^2 = 9x, x = 2, x = 4 and the x-axis in the first quadrant.

Q : 2         Find the area of the region bounded by  y^2=9x,x=2,x=4  and the x-axis in the first quadrant.
 

Answers (1)

best_answer

 

Area of the region bounded by the curve y^2=9x,x=2,x=4 and the  x-axis in the first quadrant

Area  = \int_{2}^{4}ydy = \int_{2}^{4}\sqrt{9x}dx = 3\int_{2}^{4}\sqrt{x}dx

3\left [\frac{x^{\frac{3}{2}}}{\frac{3}{2}} \right ]^4_2 = 3.\frac{2}{3}\left [ (4)^\frac{3}{2}- (2)^\frac{3}{2} \right ]

= 2\left [ 8 -2\sqrt2 \right ]

= \left [ 16 -4\sqrt2 \right ] units

Posted by

HARSH KANKARIA

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years
anam-khan

CBSE Class 12 accountancy board exam analysis 2024 out; paper rated easy, balanced

Latest Question