Q. 8.     Find the cost of polishing a circular table-top of diameter 1.6\; m, if the rate of polishing is Rs.\; 15/m^{2}. (Take \pi =3.14 )

 

Answers (1)

It is given that the diameter of a circular table is 1.6m.

We know that

Area of circle is = \pi r^2

\Rightarrow 3.14 \times \left ( \frac{1.6}{2} \right )^2 = 2.0096 \ m^2

Now, the cost of polishing at Rs.15 \; per \; m^2 is 

\Rightarrow 2.0096 \times 15 = 30.144 \ Rs

Therefore, the cost of polishing at  Rs.15 \; per \; m^2   is  Rs 30.144

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