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# Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is Rs. 15 m^ 2.

Q. 8.     Find the cost of polishing a circular table-top of diameter $1.6\; m$, if the rate of polishing is $Rs.\; 15/m^{2}$. (Take $\pi =3.14$ )

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It is given that the diameter of a circular table is 1.6m.

We know that

Area of circle is $= \pi r^2$

$\Rightarrow 3.14 \times \left ( \frac{1.6}{2} \right )^2 = 2.0096 \ m^2$

Now, the cost of polishing at $Rs.15 \; per \; m^2$ is

$\Rightarrow 2.0096 \times 15 = 30.144 \ Rs$

Therefore, the cost of polishing at  $Rs.15 \; per \; m^2$   is  Rs 30.144

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