Find the H.C.F of 12, 15 and 21 using the prime factorisation method.
12 = 2 × 2 × 3
15 = 3 × 5
21 = 3 × 7
HCF = product of the smallest power of each common prime factor in the numbers = 3
3
12=2×2×3×
15=3×5
21=3×7
The HCF of a prime factors is =3
12=2×2×3
HCF=3
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