8. Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

Answers (1)

LCM of 6, 15, 18
\begin{array}{|c|c|c|}\hline 2 & {6,15,18} \\ \hline 3 & {3,15,9} \\ \hline 3 & {1,5,3} \\ \hline 5 & {1,5,1} \\ \hline & {1,1,1} \\ \hline\end{array}

LCM = 2 \times 2 \times 3 \times 5 = 90

Required number = 90 + 5 = 95

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