2. Find the maximum and minimum values, if any, of the following functions
given by
(i) f (x) = |x + 2| - 1

Answers (1)

Given function is
f (x) = |x + 2| - 1
|x+2| \geq 0\\ |x+2| - 1 \geq -1       x \ \epsilon \ R
Hence, minimum value occurs when |x + 2| = 0
x = -2
Hence, minimum value occurs at x = -2
and minimum value is
f(-2) = |-2+2| - 1 = -1
It is clear that there is no maximum value  of the given function x \ \epsilon \ R

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