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Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.

7. Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.
 

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As we can see in the rectangle, 

By Pythagoras theorem,

(Diagonal)^2=(Length)^2+(Width)^2

Now as given in the question,

Diagonal = 41 cm.

Length = 40 cm.

So, Putting these value we get,

(41)^2=(40)^2+(Width)^2

(Width)^2=(41)^2-(40)^2

(Width)^2=1681-1600

(Width)^2=81

Width=9cm

Hence the width of the rectangle is 9 cm.

So 

The perimeter of the rectangle = 2 ( Length + Width )

                                                 = 2 ( 40 cm + 9 cm )

                                                 = 2 x 49 cm

                                                 = 98 cm 

Hence the perimeter of the rectangle is 98 cm.

 

 

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