7. Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.
 

Answers (1)

As we can see in the rectangle, 

By Pythagoras theorem,

(Diagonal)^2=(Length)^2+(Width)^2

Now as given in the question,

Diagonal = 41 cm.

Length = 40 cm.

So, Putting these value we get,

(41)^2=(40)^2+(Width)^2

(Width)^2=(41)^2-(40)^2

(Width)^2=1681-1600

(Width)^2=81

Width=9cm

Hence the width of the rectangle is 9 cm.

So 

The perimeter of the rectangle = 2 ( Length + Width )

                                                 = 2 ( 40 cm + 9 cm )

                                                 = 2 x 49 cm

                                                 = 98 cm 

Hence the perimeter of the rectangle is 98 cm.

 

 

Most Viewed Questions

Related Chapters

Preparation Products

Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 40000/-
Buy Now
Knockout NEET 2025

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 45000/-
Buy Now
NEET Foundation + Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 54999/- ₹ 42499/-
Buy Now
NEET Foundation + Knockout NEET 2024 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-
Buy Now
NEET Foundation + Knockout NEET 2025 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions