5. Find the perimeters of (ii) the rectangle BCDE in this figure. Whose perimeter is greater?
The perimeter of = AB + BE + AE
Noe, The LCM of 2,4 and 5 is 20. So let's make the denominator of all fraction, 20.
The perimeter of :
The perimeter of rectangle BCDE = 2 x ( BE + ED )
The LCM of 4 and 6 is 12. So let's make the denominator of both fractions equal to 12.
Hence The perimeter of the Triangle is and the perimeter of Rectangle is .
Now, we have
LCM of 20 and 6 is 60, so let's make denominator of both fraction equal to 60.
Now, Since 531 > 470
Area of Triangle > Area of Rectangle.