# 17) Find the points on the curve $y = x ^3$ at which the slope of the tangent is equal to the y-coordinate of the point.

Given equation of curve is  $y = x ^3$
Slope of tangent = $\frac{dy}{dx} = 3x^2$
it is given that  the slope of the tangent is equal to the y-coordinate of the point
$3x^2 = y$
We have  $y = x ^3$
$3x^2 = x^3\\ 3x^2 - x^3=0\\ x^2(3-x)=0\\ x= 0 \ \ \ \ \ \ \ \ and \ \ \ \ \ \ \ \ \ \ x = 3$
So, when x = 0 , y = 0
and when x = 3 , $y = x^3 = 3^3 = 27$

Hence, the coordinates are (3,27) and (0,0)

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