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Find the principal values of the following:

    8. \cot^{-1}(\sqrt3)

Answers (1)


Let us assume that \cot^{-1}(\sqrt3) = x , then we can write in other way,

\cot x = (\sqrt3)   or   

\cot (\frac{\pi}{6}) = (\sqrt3).

Hence when   x=\frac{\pi}{6}  we have \cot (\frac{\pi}{6}) = (\sqrt3).

and the range of principal values of \cot^{-1} lies in \left ( 0, \pi \right ).

Then the principal value of \cot^{-1}(\sqrt3) is \frac{\pi}{6}


Posted by

Divya Prakash Singh

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