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# Find the remainder when x ^3 + 3x ^2 + 3x + 1 is divided by (i) x + 1

1.(i)  Find the remainder when $x^3 + 3x^2 +3x + 1$ is divided by

(i)    $x + 1$

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When we divide  $x^3 + 3x^2 +3x + 1$  by  $x + 1$

By long division method, we will get

Therefore, remainder is  $0$

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