Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the slope of the tangent to curve y = x ^3 – x + 1 at the point whose x-coordinate is 2.

3) Find the slope of the tangent to curvey = x ^3 - x +1 at the point whose x-coordinate is 2.

Answers (1)

best_answer

Given curve is,
y = x ^3 - x +1
The slope of the tangent at x = 2 is given by
\left ( \frac{dy}{dx} \right )_{x=2} = 3x^2 - 1 = 3(2)^2 - 1= 3\times 4 - 1 = 12 - 1 = 11
Hence, the slope of the tangent at point x = 2 is 11

Posted by

Gautam harsolia

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

‘Stop defending your so-called flawless OSM’: Class 12 students slam CBSE over blurred answer sheets
anam-khan

'CBSE failed us, again!': Board faces backlash as Class 12 re-evaluation portal remains inaccessible
anam-khan

CBSE Class 12 re-evaluation portal faces technical glitch, services to resume by 2 pm

Latest Question