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# Find the slope of the tangent to the curve y = x ^3 – 3 x + 2 at the point whose x-coordinate is 3.

4) Find the slope of the tangent to the curve$y = x ^3 - 3x +2$ at the point whose x-coordinate is 3.

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Given curve is,
$y = x ^3 - 3x +2$
The slope of the tangent at x = 3 is given by
$\left ( \frac{dy}{dx} \right )_{x=3} = 3x^2 - 3 = 3(3)^2 - 3= 3\times 9 - 3 = 27 - 3 = 24$
Hence, the slope of tangent at point x = 3 is 24

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