1.  Find the value of the unknown x in the following diagrams

        

Answers (1)

As we know that the sum of the internal angles of the triangle is equal to 180^0. So,

i) x+50^0+60^0=180^0

x=180^0-50^0-60^0

x=70^0

ii) x+30^0+90^0=180^0

x=180^0-30^0-90^0

x=60^0

iii) x+30^0+110^0=180^0

x=180^0-30^0-110^0

x=40^0

iv) x+x+50^0=180^0

2x=180^0-50^0

2x=130^0

x=65^0

v) x+x+x=180^0

3x=180^0

x=60^0

vi) x+2x^0+90^0=180^0

3x=180^0-90^0

3x=90^0

x=30^0

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