Q : 3       Find values of k if area of triangle is 4 sq. units and vertices are

              (ii)   (-2,0), (0,4), (0,k)

Answers (1)

The area of the triangle is given by the formula:

\triangle = \frac{1}{2} \begin{vmatrix} -2 &0 &1 \\ 0 & 4 & 1\\ 0& k & 1 \end{vmatrix} = 4\ sq.\ units.

Now, calculating the area:

= \frac{1}{2} \left | -2(4-k)-0(0-0)+1(0-0) \right | = \frac{1}{2} \left | -8+2k \right | = 4

or  -8+2k =\pm 8       

 Therefore we have two possible values of 'k' i.e.,  k = 8  or  k = 0.

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