# 5. Following table shows the points of each player scored in four games:        Now answer the following questions: (i) Find the mean to determine A’s average number of points scored per game. (ii) To find the mean number of points per game for C, would you divide the total points by 3 or by 4? Why? (iii) B played in all the four games. How would you find the mean? (iv) Who is the best performer?

Given,

We know,

$Arithmetic\: mean =\frac{sum\ of\ observations}{number\ of\ observation}$

(i) Therefore, A's average number of points scored per game

$\\ = \frac{14+16+10+10}{4} \\ = \frac{50}{4} \\ \\ = 12.5$

(ii) Number of games C played = 3

Therefore, to find the mean, we will divide by 3

Mean of C =

$\\ = \frac{8+11+13}{3} \\ = \frac{32}{3} \\ \\ = 10.67$

(iii) Although he scored 0 in a match, he played all 4 games. Therefore, we will divide by 4.

Mean of B =

$\\ = \frac{0+8+6+4}{4} \\ = \frac{18}{4} \\ \\ = 4.5$

(iv) Mean of A = $12.5$

Mean of B = $4.5$

Mean of C =  $10.67$

Since, A has the highest mean, A is the best performer.

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