Q&A - Ask Doubts and Get Answers
Q

For what values of a the function f given by f (x) is equal to x is raised to 2 plus ax plus 1 is increasing on [1, 2]?

14) For what values of a the function f given by f (x) = x^2 + ax + 1  is increasing on
[1, 2]?

Answers (1)
Views

Given function is,
f (x) = x^2 + ax + 1
f^{'}(x) = 2x + a
Now,  we can clearly see that  for every  value of  a > -2
 f^{'}(x) = 2x + a  > 0 
Hence, f (x) = x^2 + ax + 1   is increasing for every value of   a > -2   in the interval [1,2]
         

Exams
Articles
Questions