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# From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed.

Q. 10.     From a circular card sheet of radius $14\; cm$, two circles of radius $3.5\; cm$ and a rectangle of length $3\; cm$ and breadth $1\; cm$ are removed.(as shown in the adjoining figure). Find the area of the remaining sheet. (Take $\pi =\frac{22}{7}$ )

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It is given that radius of circular card sheet is $14\; cm$

Now, we know that

Area of circle (A) = $\pi r^2$

$\Rightarrow \pi r^2= \frac{22}{7}\times (14)^2= 616 \ cm^2$                                      - (i)

Now,

Area of circle with radius 3.5 cm is

$\Rightarrow \pi r^2= \frac{22}{7}\times (3.5)^2= 38.5 \ cm^2$

Area of two such circle is = $38.5 \times 2 = 77 \ cm^2$                  -(ii)

Now, Area of rectangle = $l \times b$

$\Rightarrow l \times b = 3 \times 1 = 3\ cm^2$                                                   -(iii)

Now, the remaining area is (i) - [(ii) + (iii)]

$\Rightarrow 616- [77+3]\Rightarrow 616-80 = 536 \ cm^2$

Therefore,  area of the remaining sheet  is  $536 \ cm^2$

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