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  • From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed.

Q. 10.     From a circular card sheet of radius 14\; cm, two circles of radius 3.5\; cm and a rectangle of length 3\; cm and breadth 1\; cm are removed.(as shown in the adjoining figure). Find the area of the remaining sheet. (Take \pi =\frac{22}{7} )

                  

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It is given that radius of circular card sheet is 14\; cm

Now, we know that

Area of circle (A) = \pi r^2

\Rightarrow \pi r^2= \frac{22}{7}\times (14)^2= 616 \ cm^2                                      - (i)

Now,

Area of circle with radius 3.5 cm is

\Rightarrow \pi r^2= \frac{22}{7}\times (3.5)^2= 38.5 \ cm^2                                 

Area of two such circle is = 38.5 \times 2 = 77 \ cm^2                  -(ii)

Now, Area of rectangle = l \times b

\Rightarrow l \times b = 3 \times 1 = 3\ cm^2                                                   -(iii)

Now, the remaining area is (i) - [(ii) + (iii)]

\Rightarrow 616- [77+3]\Rightarrow 616-80 = 536 \ cm^2

Therefore,  area of the remaining sheet  is  536 \ cm^2

Posted by

Gautam harsolia

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