Q

# Given AB of length 3.9 cm, construct PQ such that the length of PQ is twice that of AB . Verify by measurement. (Hint : Construct PX such that length of PX = length of AB ; then cut off XQ such that XQ also has the length of AB.)

Q4.    Given $\overline{AB}$ of length 3.9 cm, construct $\overline{PQ}$ such that the length of $\overline{PQ}$ is twice that of $\overline{AB}$. Verify by measurement.

(Hint: Construct $\overline{PX}$ such that length of $\overline{PX}$ = length of $\overline{AB}$ ; then cut off $\overline{XQ}$ such that $\overline{XQ}$ also has the length of $\overline{AB}$ .)

Views

The steps of constructions are following:

(i) Draw a line ′l′.

(ii) Construct $\bar{PX}$ such that length of $\bar{PX}$ = length of $\bar{AB}$

(iii) Then cut of $\bar{XQ}$ such that $\bar{XQ}$ also has the length of $\bar{AB}$ .

(iv) Thus the length of $\bar{PX}$  and the length of $\bar{XQ}$ added together make twice the length of $\bar{AB}$.

Verification:

By measurement we find that PQ = 7.8 cm

= 3.9 cm + 3.9 cm = $\bar{AB} + \bar{AB}$   = $2\times\bar{AB} .$

Exams
Articles
Questions