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# Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them to get an equivalent resistance of (iv) (6 / 11) Ω

3.20 (b) Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them
to get an equivalent resistance of (iv)$\frac{6}{11}\Omega$

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Connect all three resistors in parallel.

Equivalent Resistance is  R =  1/(1/1 + 1/2 + 1/3) = (1x 2 x 3)/(6 + 3 + 2)

R = 6/11 Ω

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