7.35     How are XeO_{3} and XeOF_{4}  prepared?

Answers (1)
  • When we do Hydrolysis of XeF_4and XeF_6 with water we get XeOF_3                               

                 6XeF_4+12H_2O\rightarrow 4Xe+2XeO_3+24HF+3O_2

                     XeF_6+3H_2O\rightarrow XeO_3+6HF

  • And  Partial hydrolysis of XeF_6 gives us, XeOF_4

                  XeF_6+H_2O\rightarrow XeOF_4+2HF

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