# How will you construct a 15° angle?

D Divya Prakash Singh

First, we make $30^{\circ},$ and then its bisector.

The steps of constructions are:

1. Draw a ray OA.

2. Taking O as the center and any radius of your own choice, draw an arc cutting OA at B.

3. Now, taking B as center and with the same radius as before, draw an arc intersecting the previously drawn arc at point C.

4. Draw the ray OD passing through the C.

Thus, $\angle AOD = 60^{\circ}$

Now, we draw bisector of $\angle AOD$

5. Taking C and D as the center, with radius more than $\frac{1}{2}CD$, draw arcs intersecting at E.

6. Join OE.

Thus, $\angle AOE = 30^{\circ}$

Now, we draw the bisector of $\angle AOD$

7. Mark point P where the ray OE intersects the arc.

8. Taking P and B as center, with having the radius more than $\frac{1}{2}PB$, draw arcs intersecting at F.

9. Join OF

Thus, $\angle AOF = 15^{\circ}.$

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