# 13.3    How will you convert                (iii)  $\inline Cl-(CH_{2})_{4}-Cl$   into $\inline hexan-1$ ,$\inline 6-diamine?$

ON reacting the given reactant with ethanolic sodium cyanide, the CN molecules replace both chlorine atom. And after that catalytic hydrogenation, we get our desired product. (reduce the CN to $-CH_{2}NH_{2}$ in both sides)