13.5     How will you convert:

                 (i) Ethanoic acid into methanamine

Answers (1)
M manish

Ethanoic acid on reacting with SOCl_{2} replaces the OH by Cl and then reacts it with an excess of ammonia molecule to produce methanamide (CH_{3}CONH_{2}) which by Hoffmann bromamide degradation reaction gives us desired product (methenamine)

\\CH_{3}COOH+SOCl_{2}\rightarrow CH_{3}COCl\overset{NH_{3}(excess)}{\rightarrow}CH_{3}CONH_{2} \overset{Br_{2}+KOH}{\rightarrow}CH_{3}NH_{2}

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