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# (i) Is 10 × (6 – (–2)] = 10 × 6 – 10 × (–2)?

(i) Is 10 × (6 – (–2)] = 10 × 6 – 10 × (–2)?

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L.H.S = $10 \times [6 - (-2)] = 10\times[6+2] = 10\times8 = 80$

R.H.S = $10 \times 6- 10 \times (-2) = 60 - (-20) = 60+20 = 80$

$\therefore$ L.H.S = R.H.S

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