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5. If a population growing exponentially doubles in size in 3 years, what is the intrinsic rate of increase (r) of the population?

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A population grows exponentially when ample amounts of food resources are available to the individual. The exponential growth can be calculated by the following exponential growth equation:

Nt = No ert

Where,

Nt= Population density after time t

NO= Population density at time zero

r = Intrinsic rate of natural increase

= Base of natural logarithms (2.71828)

Now, as per the question,

Present population density = x

Then,

Population density after two years = 2x

t = 3 years

Substituting these values in the formula, we get:

⇒ 2x = x e3r

⇒ 2 = e3r

Applying log on both sides:

⇒ log 2 = 3r log e

Therefore, the intrinsic rate of increase will be 0.2311.

Posted by

Sonika

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