# Q.  13 If $f : R \rightarrow R$ be given by $f(x) = (3 - x^3)^{\frac{1}{3}}$, then $fof(x)$ is (A) $x^{\frac{1}{3}}$(B) $x^3$(C) $x$(D) $(3 - x^3)$

$f(x) = (3 - x^3)^{\frac{1}{3}}$

$fof(x)$$=f(f(x))=f((3-x^{3})^{\frac{1}{3}})$

$=[3- ((3-x^{3})^{\frac{1}{3}})^{3}]^{\frac{1}{3}}$

$=([3- ((3-x^{3})]^{\frac{1}{3}})$

$= (x^{3})^{\frac{1}{3}}$

$=x$

Thus,$fof(x)$ is x.

Hence, option c is correct answer.

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