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13. If $\sin^{-1}x = y$ then

(A)     $0\leq y \leq \pi$

(B)     $-\frac{\pi}{2} \leq y \leq \frac{\pi}{2}$

(C)      $0 < y < \pi$

(D)      $-\frac{\pi}{2} < y < \frac{\pi}{2}$

Answers (1)

D Divya Prakash Singh

Given if $\sin^{-1}x = y$ then,

As we know that the $\sin^{-1}$ can take values between $\left [ \frac{-\pi}{2}, \frac{\pi}{2} \right ].$

Therefore, $-\frac{\pi}{2} \leq y \leq \frac{\pi}{2}$ .

Hence answer choice (B) is correct.

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