Q

# if sin inverse x= y then (A) 0 less than or equal to y less than or equal to pi (B) - pi / 2 is less than or equal to y is less than or equal to pi / 2 (C) 0 < y < pi (D) - pi / 2 < y < pi / 2

13. If $\sin^{-1}x = y$ then

(A)    $0\leq y \leq \pi$

(B)    $-\frac{\pi}{2} \leq y \leq \frac{\pi}{2}$

(C)     $0 < y < \pi$

(D)     $-\frac{\pi}{2} < y < \frac{\pi}{2}$

Views

Given if  $\sin^{-1}x = y$  then,

As we know that the $\sin^{-1}$ can take values between $\left [ \frac{-\pi}{2}, \frac{\pi}{2} \right ].$

Therefore, $-\frac{\pi}{2} \leq y \leq \frac{\pi}{2}$.

Hence answer choice (B) is correct.

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