13. If \sin^{-1}x = y then

    (A)    0\leq y \leq \pi

    (B)    -\frac{\pi}{2} \leq y \leq \frac{\pi}{2}

    (C)     0 < y < \pi

    (D)     -\frac{\pi}{2} < y < \frac{\pi}{2}

Answers (1)

Given if  \sin^{-1}x = y  then,

As we know that the \sin^{-1} can take values between \left [ \frac{-\pi}{2}, \frac{\pi}{2} \right ].

Therefore, -\frac{\pi}{2} \leq y \leq \frac{\pi}{2}.

Hence answer choice (B) is correct.

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