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If the volume of a right circular cone of height 9 cm is 48 π cm^3, find the diameter of its base.

Q : 4    If the volume of a right circular cone of height 9 cm is \small 48\pi \hspace{1mm}cm^3, find the diameter of its base.
 

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Given,

Height of the cone = h =9\ cm

Let the radius of the base of the cone be r\ cm

We know,
The volume of a right circular cone = \frac{1}{3}\pi r^2 h

\therefore \frac{1}{3}\times\pi\times r^2\times9 = 48\pi

\\ \Rightarrow 3r^2 = 48 \\ \Rightarrow r^2 = 16\\ \Rightarrow r = 4\ cm

Therefore the diameter of the right circular cone is 8\ cm

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