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1.27) In a certain region of space, electric field is along the z-direction throughout. The magnitude of electric field is, however, not constant but increases uniformly along the positive z-direction, at the rate of 10^{5}NC^{-1} per metre. What are the force and torque experienced by a system having a total dipole moment equal to 10^{-7} Cm in the negative z-direction ?

Answers (1)

Force on a charge F=qE

but here E is varying along the Z direction. 

Force can be written as,

F=q\frac{dE}{dz}dz=P\frac{dE}{dz}=10^{-7}\times10^5=10^{-2}N

Torque experienced =0 since both dipole and electric field are in the Z direction. The angle between dipole and the electric field is 180 degrees

\tau = \mathbf{P}\times \mathbf{E}=PEsin\180=0

Posted by

Safeer PP

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