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# In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.

Q : 8    In a hot water heating system, there is a cylindrical pipe of length $\small 28\hspace{1mm}m$ and diameter $\small 5\hspace{1mm}cm$. Find the total radiating surface in the system.

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Given,

Length of the cylindrical pipe = $l = \small 28\hspace{1mm}m$

Diameter =  $\small d = 5\hspace{1mm}cm = 0.05\ m$

The total radiating surface will be the curved surface of this pipe.

We know,

The curved surface area of a cylindrical pipe of radius $r$ and length $l$ = $2\pi r l$

$\therefore$ CSA of this pipe =

$= 2\times\frac{22}{7}\times\frac{0.05}{2}\times28$

$\\ = 22\times0.05\times4 \\ = 4.4\ m^2$

Therefore, the total radiating surface of the system is $4.4\ m^2$

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