10(a) In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 20 \times 10 ^{10 }Hz  and amplitude 48 Vm ^{-1}

What is the wavelength of the wave?

Answers (1)
S Sayak

Frequency(\nu) =20\times1010 Hz

E0 = 48 Vm-1

 Wavelength(\lambda) =\frac{Speed\ of\ light(c)}{Frequency (\nu )}

=\frac{3\times 10^{8}}{20\times 10^{10}}

=1.5 mm

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