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# In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 1010 Hz and amplitude 48 V m raised to –1.

10(a) In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of $20 \times 10 ^{10 }Hz$  and amplitude $48 Vm ^{-1}$

What is the wavelength of the wave?

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Frequency($\nu$) =20$\times$1010 Hz

E0 = 48 Vm-1

$Wavelength(\lambda) =\frac{Speed\ of\ light(c)}{Frequency (\nu )}$

=$\frac{3\times 10^{8}}{20\times 10^{10}}$

$=1.5 mm$

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