Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

10(a) In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of $20 \times 10 ^{10 }Hz$ and amplitude $48 Vm ^{-1}$

What is the wavelength of the wave?

Answers (1)

best_answer

Frequency( $\nu$ ) =20 $\times$ 10¹⁰ Hz

E₀ = 48 Vm^-1

$Wavelength(\lambda) =\frac{Speed\ of\ light(c)}{Frequency (\nu )}$

= $\frac{3\times 10^{8}}{20\times 10^{10}}$

$=1.5 mm$

Posted by

Sayak

View full answer

Crack CUET with india's "Best Teachers"

HD Video Lectures
Unlimited Mock Tests
Faculty Support

cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE admit card 2025 out for Class 10, 12 supplementary exams

anam-khan

CBSE Class 10, 12 practical exams 2025 for compartment students from July 10; detailed guidelines issued

anam-khan

CBSE Central Sector Scheme of Scholarship 2025 applications open on scholarships.gov.in

Latest Question