1 In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
(d) 5y + 8 = 0
Given the equation of plane is or we can write
So, the direction ratios of normal from the above equation are, .
Therefore
Then dividing both sides of the plane equation by , we get
So, this is the form of the plane, where are the direction cosines of normal to the plane and d is the distance of the perpendicular drawn from the origin.
The direction cosines of the given line are and the distance of the plane from the origin is units.