1. In Fig. 6.28, find the values of x and y and then show that AB || CD.

                

Answers (1)


Given that,
In the figure, CD and PQ intersect at  F
Therefore, y =130^0  (vertically opposite angles)

PQ is a straight line. So, 
\\x + 50^0 =180^0\\ x = 130^0

Hence AB || CD (since x and are y alternate interior angles)

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