6. In Fig. 6.33, PQ and RS are two mirrors placed parallel to each other. An incident ray AB strikes the mirror PQ at B, and the reflected ray moves along the path BC and strikes the mirror RS at C and again reflects along CD. Prove that AB CD.
Draw a ray BL PQ and CM RS
Since PQ || RS (Given)
So, BL || CM and BC is a transversal
LBC = MCB (Alternate interior angles).............(i)
It is known that, angle of incidence = angle of reflection
So, ABL = LBC and MCB = MCD
..................(ii)
Adding eq (i) and eq (ii), we get
ABC = DCB
Both the interior angles are equal
Hence AB || CD